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What will be the molality of the solution containing 18.25 g of HCl gas in 500 g of water? - Chemistry

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प्रश्न

What will be the molality of the solution containing 18.25 g of \[\ce{HCl}\] gas in 500 g of water?

पर्याय

  • 0.1 m

  • 1 M

  • 0.5 m

  • 1 m

MCQ

उत्तर

1 m

Explanation:

The number of moles is given by the following formula,

Moles = `"Mass"/"Molar mass"`  ......(1)

The number of moles of \[\ce{HCl}\] is calculated by using equation (1) as follows,

Moles of HCl = `(18.25 g)/((36.5 g)/(mol)` = 0.5 mol

The morality (m) is given by the formula:

m = `"n"/"mass of solvent"_((kg))`

On substituting the values in the above equation:

Molality = `(0.5  mol xx 1000  kg)/500` = 1 m

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Some Basic Concepts of Chemistry - Multiple Choice Questions (Type - I) [पृष्ठ २]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 1 Some Basic Concepts of Chemistry
Multiple Choice Questions (Type - I) | Q 7 | पृष्ठ २

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