Question

What will be the volume of oxygen gas produced, if the reaction \[\ce{2KClO_{3(s)} -> 2KCl_{(s)} + 3O_{2(g)}}\]; ΔH° = - 78 kJ is carried out at S.T.P.?

पर्याय

• 44.8 L

• 48.0 L

• 67.2 L

• 22.4 L

Answer 1

67.2 L

Explanation:

\[\ce{2KClO_{3(s)} -> 2KCl_{(s)} + 3O_{2(g)}}\]

At STP, 1 mole of O₂ = 22.4 L

∴ 3 mole of O₂ = 22.4 × 3 = 67.2 L