Question

When 1 kg of ice at 0°C melts to water at 0°C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/°C is:

पर्याय

• 293 cal/k

• 305 cal/k

• 257 cal/k

• 423 cal/k

Answer 1

293 cal/k

Explanation:

M = 1 kg, L = 80 cal/°C

ΔS = `"ML"/"T"`

= `(1000 xx 80)/273`

= 293 cal/k