Question

When a beam of 10.6 eV photons of intensity 2.0 W/m² falls on a platinum surface of area 1.0 × 10^-4 m², only 53% of the incident photons eject photoelectrons. The number of photoelectrons emitted per second is ______.

पर्याय

• 6.25 × 10¹³

• 11.79 × 10¹³

• 6.25 × 10¹¹

• 11.79 × 10¹¹

Answer 1

When a beam of 10.6 eV photons of intensity 2.0 W/m² falls on a platinum surface of area 1.0 x 10^-4 m², only 53% of the incident photons eject photoelectrons. The number of photoelectrons emitted per second is 6.25 × 10¹¹.

Explanation:

Number of photoelectrons emitted per second

N = `"IA"/"energy" xx "n"%`

`= (2 xx 1 xx 10^-4)/(10.6 xx 1.6 xx 10^-19) xx 53/100`

`= 62.5 xx 10^11`