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प्रश्न
Which of the following is incorrect?
पर्याय
\[\ce{∧^0_{m(NaCl)} - ∧^0_{m(NaBr)} = ∧^0_{m(KCl)} - ∧^0_{m(KBr)}}\]
\[\ce{∧^0_{m(H_2O)} - ∧^0_{m(HCl)} = ∧^0_{m(NaOH)} - ∧^0_{m(NaCl)}}\]
\[\ce{∧^0_{m(NaI)} - ∧^0_{m(NaBr)} = ∧^0_{m(NaBr)} - ∧^0_{m(KBr)}}\]
\[\ce{∧^0_{m(NaCl)} - ∧^0_{m(KCl)} = ∧^0_{m(NaBr)} - ∧^0_{m(KBr)}}\]
उत्तर
\[\ce{∧^0_{m(NaI)} - ∧^0_{m(NaBr)} = ∧^0_{m(NaBr)} - ∧^0_{m(KBr)}}\]
Explanation:
(1) \[\ce{∧^0_{m(NaCl)} - ∧^0_{m(NaBr)} = ∧^0_{m(KCl)} - ∧^0_{m(KBr)}}\]
\[\ce{(λ^0_{Na^+} + λ^0_{Cl^-}) - (λ^0_{Na^+} + λ^0_{Br^-}) = (λ^0_{K^+} + λ^0_{Cl^-}) - (λ^0_{K^+} + λ^0_{Br^-})}\]
\[\ce{λ^0_{Cl^-} - λ^0_{Br^-} = λ^0_{Cl^-} - λ^0_{Br^-}}\]
(2) \[\ce{∧^0_{m(H_2O)} - ∧^0_{m(HCl)} = ∧^0_{m(NaOH)} - ∧^0_{m(NaCl)}}\]
\[\ce{(λ^0_{H^+} + λ^0_{OH^-}) - (λ^0_{H^+} + λ^0_{Cl^-}) = (λ^0_{Na^+} + λ^0_{OH^-}) - (λ^0_{Na^+} + λ^0_{Cl^-})}\]
\[\ce{λ^0_{OH^-} - λ^0_{Cl^-} = λ^0_{OH^-} - λ^0_{Cl^-}}\]
(3) \[\ce{∧^0_{m(NaI)} - ∧^0_{m(NaBr)} = ∧^0_{m(NaBr)} - ∧^0_{m(KBr)}}\]
\[\ce{(λ^0_{Na^+} + λ^0_{I^-}) - (λ^0_{Na^+} + λ^0_{Br^-}) = (λ^0_{Na^+} + λ^0_{Br^-}) - (λ^0_{K^+} + λ^0_{Br^-})}\]
\[\ce{λ^0_{I^-} - λ^0_{Br^-} ≠ λ^0_{Na^+} + λ^0_{K^+}}\]
(4) \[\ce{∧^0_{m(NaCl)} - ∧^0_{m(KCl)} = ∧^0_{m(NaBr)} - ∧^0_{m(KBr)}}\]
\[\ce{(λ^0_{Na^+} + λ^0_{Cl^-}) - (λ^0_{K^+} + λ^0_{Cl^-}) = (λ^0_{Na^+} + λ^0_{Br^-}) - (λ^0_{K^+} + λ^0_{Br^-})}\]
\[\ce{λ^0_{Na^+} - λ^0_{K^+} = λ^0_{Na^+} - λ^0_{K^+}}\]
