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प्रश्न
Which term of the A.P. 5, 15, 25, .......... will be 130 more than its 31st term?
उत्तर
Here, a = 5 and d = (15 – 5) = 10
The 31st term is given by
T31 = a + (31 – 1)d
= a + 30d
= 5 + 30 × 10
= 305
∴ Required term = (305 + 130) = 435
Let this be the nth term.
Then, Tn = 435
`\implies` 5 + (n – 1) × 10 = 435
`\implies` 10n = 440
`\implies` n = 44
Hence, the 44th term will be 130 more than its 31st term.
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