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Would You Expect the Second Electron Gain Enthalpy of O as Positive, More Negative Or Less Negative than the First? Justify Your Answer. - Chemistry

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प्रश्न

Would you expect the second electron gain enthalpy of O as positive, more negative or less negative than the first? Justify your answer.

थोडक्यात उत्तर

उत्तर १

When an electron is added to O atom to form O ion, energy is released. Thus, the first electron gain enthalpy of O is negative.

\[\ce{O_{(g)} + e-  →  O-_{(g)}}\]

On the other hand, when an electron is added to O- ion to form O2- ion, energy has to be given out in order to overcome the strong electronic repulsions. Thus, the second electron gain enthalpy of O is positive.

\[\ce{O_{(g)} + e-  →  O-_{(g)}}\]

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उत्तर २

\[\ce{O_{(g)} + e-  →  O-_{(g)}}\] (∆ eg H = – 141 kJ mol -1)

\[\ce{O-_{(g)} + e-  →  O^{2-}_{(g)}}\] (∆ eg H = + 780 kJ mol -1)

The first electron gain enthalpy of oxygen is negative because energy is released when a gaseous atom accepts an electron to form monovalent anion. The second electron gain enthalpy is positive because energy is needed to overcome the force of repulsion between monovalent anion and second incoming electron.

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पाठ 3: Classification of Elements and Periodicity in Properties - EXERCISES [पृष्ठ ९७]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
पाठ 3 Classification of Elements and Periodicity in Properties
EXERCISES | Q 3.21 | पृष्ठ ९७

संबंधित प्रश्‍न

What is the significance of the terms - ‘isolated gaseous atom’ and ‘ground state’ while defining the ionization enthalpy and electron gain enthalpy?

Hint: Requirements for comparison purposes.


Describe the theory associated with the radius of an atom as it gains an electron.


Describe the theory associated with the radius of an atom as it loses an electron.


Which of the following pair of elements would have a more negative electron gain enthalpy?

O or F


The formation of the oxide ion, \[\ce{O2- (g)}\], from oxygen atom requires first an exothermic and then an endothermic step as shown below:

\[\ce{O (g) + e- -> O- (g) ; ∆H^Θ = - 14 kJ mol^{-1}}\]

\[\ce{O- (g) + e- -> O^{2-} (g) ; ∆H^Θ = + 780 kJ mol^{-1}}\]

Thus process of formation of \[\ce{O^{2-}}\] in gas phase is unfavourable even though \[\ce{O^{2-}}\] is isoelectronic with neon. It is due to the fact that,


Which of the following elements will gain one electron more readily in comparison to other elements of their group?

(i) \[\ce{S (g)}\]

(ii) \[\ce{Na (g)}\]

(iii) \[\ce{O (g)}\]

(iv) \[\ce{Cl (g)}\]


Which of the following statements are correct?

(i) Helium has the highest first ionisation enthalpy in the periodic table.

(ii) Chlorine has less negative electron gain enthalpy than fluorine.

(iii) Mercury and bromine are liquids at room temperature.

(iv) In any period, atomic radius of alkali metal is the highest.


In which of the following options the order of arrangement does not agree with the variation of the property indicated against it?

(i) \[\ce{Al^{3+} < Mg^{2+} < Na+ < F-}\] (increasing ionic size)

(ii) \[\ce{B < C < N < O}\] (increasing first ionisation enthalpy)

(iii) \[\ce{I < Br < Cl < F}\] (increasing electron gain enthalpy)

(iv) \[\ce{Li < Na < K < Rb}\] (increasing metallic radius)


Match the correct ionisation enthalpies and electron gain enthalpies of the following elements.

Elements   ∆H1 ∆H2 egH
(i) Most reactive non-metal A. 419 3051 – 48
(ii) Most reactive metal B. 1681 3374 – 328
(iii) Least reactive element e C. 738 1451 – 40
(iv) Metal forming binary halide D. 2372 5251 + 48

Electronic configuration of some elements is given in Column I and their electron gain enthalpies are given in Column II. Match the electronic configuration with electron gain enthalpy.

Column (I) Column (II)
Electronic configuration Electron gain enthalpy/kJ mol–1
(i) 1s2 2s2 sp6 (A) – 53
(ii) 1s2 2s2 2p6 3s1 (B) – 328
(iii) 1s2 2s2 2p5 (C) – 141
(iv) 1s2 2s2 2p4 (D) + 48

Assertion (A): Electron gain enthalpy becomes less negative as we go down a group.

Reason (R): Size of the atom increases on going down the group and the added electron would be farther from the nucleus.


Discuss the factors affecting electron gain enthalpy and the trend in its variation in the periodic table.


Assertion: The most electronegative element in the periodic table is F.

Reason: Fluorine has the highest negative electron gain enthalpy.


The correct order of electron gain enthalpy (−ve value) is ______.


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