Advertisements
Advertisements
प्रश्न
Write balanced equation for the following conversion:
a. Cyclopropane carboxylic acid to cyclopropylmethanol.
b. Acetyl chloride to benzyl methyl ketone using dialkyl cadmium.
उत्तर
a. Cyclopropane carboxylic acid to cyclopropyl methanol:
Strong reducing agent like lithium aluminium hydride or diborane reduces cyclopropane carboxylic acid to cyclopropyl methanol.
b. Acetyl chloride to benzyl methyl ketone using dialkyl cadmium:
\[\begin{array}{cc}
\ce{O}\phantom{....................................}\ce{O}\phantom{..............}\\
||\phantom{....................................}||\phantom{..............}\\
\ce{\underset{\text{Acetyl chloride}}{2CH3-C-CL} + \underset{\text{Dibenzyl cadmium}}{(C6H5CH2)2Cd -> \underset{\text{Benzyl methyl ketone}}{2CH3-C-CH2C6H5} + CdCl2}}\\
\end{array}\]
