Advertisements
Advertisements
प्रश्न
Write the first five terms of the following sequences whose nth terms are:
`a_n = 3^n`
उत्तर
`a_n = 3^n`
Here, the nth term is given by the above expression. So, to find the first term we use
n = 1 we get
`a_1 = 3^(1)`
= 3
Similarly, we find the other four terms,
Second term (n = 2)
`a_2 = 3^(2)`
= (3)(3)
= 9
Third term (n = 3)
`a_3 = 3^(3)`
= (3)(3)(3)
= 27
Fourth term (n = 4)
`a_4 = 3^(4)`
= (3)(3)(3)(3)
= 81
Fifth term (n = 5)
`a_5 = 3^(5)`
= (3)(3)(3)(3)(3)
= 243
Therefore, the first five terms for the given sequence are
`a_1 = 3, a_2 = 9, a_3 = 27, a_4 = 81. a_5 = 243`
APPEARS IN
संबंधित प्रश्न
Fill in the blank in the following table, given that a is the first term, d the common difference, and an nth term of the AP:
a | d | n | an |
7 | 3 | 8 | ______ |
Find the number of terms in the following A.P.: 7, 13, 19, ..., 205.
In an AP, if the common difference (d) = –4, and the seventh term (a7) is 4, then find the first term.
Find the next five terms of the following sequences given by:
`a_1 = -1, a_n = (a_n - 1)/n, n>= 2`
Find the 10th term from the end of the A.P. 8, 10, 12, ..., 126.
Show that each of the progressions given below is an AP. Find the first term, common difference and next term of each.
(v) `sqrt(20)`, `sqrt(45)`, `sqrt(80)`, `sqrt(125)`,.........
Reshma wanted to save at least Rs 6,500 for sending her daughter to school next year (after 12 month.) She saved Rs 450 in the first month and raised her savings by Rs 20 every next month. How much will she be able to save in next 12 months? Will she be able to send her daughter to the school next year?
What value is reflected in this question ?
The 11th term of the AP: `-5, (-5)/2, 0, 5/2, ...` is ______.
The 10th term from the end of the A.P. -5, -10, -15,…, -1000 is ______.
Write the first three terms of the APs when a and d are as given below:
a = `sqrt(2)`, d = `1/sqrt(2)`