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प्रश्न
Write the expression for the solubility product of Ca3(PO4)2.
उत्तर
\[\ce{\underset{(s)}{Ca3(PO4)2} ⇌ \underset{(3s)}{3Ca^{2+}} + \underset{(2s)}{2PO^{-3}_4}}\]
Solubility of Ca3(PO4)2 is,
Ksp = \[\ce{[Ca^{2+}]^3 [PO^{3-}_{4}]^2}\]
Ksp = (3s)3 (2s)2
Ksp = (27s3) (4s2)
Ksp = 108s5
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