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प्रश्न
`x^2-(1+sqrt2)x+sqrt2=0`
उत्तर
`x^2-(1+sqrt2)x+sqrt2=0`
⇒` x^2-x-sqrt2x+sqrt2=0`
⇒`x(x-1)-sqrt2(x-1)=0`
⇒` (x-sqrt2)(x-1)=0`
⇒`x=sqrt2=0 or x-1=0 `
⇒`x=sqrt2 or x=1`
Hence, the roots of the equation are `sqrt2` and 1
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