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प्रश्न
x varies inversely as twice of y. Given that when y = 6, the value of x is 4. Find the value of x when y = 8
उत्तर
Given x varies inversely as twice of y.
| x | 4 | x |
| y | 6 | 8 |
x1y1 = x2y2
4 × 6 = x × 8
x = `(4 xx 6)/8`
x = 3
When y = 8
x = 3
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