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प्रश्न
Xenon crystallizes in fee lattice and the edge length of unit cell is 620 pm. What is the radius of Xe atom?
पर्याय
536.9 pm
438.5 pm
265.5 pm
219.2 pm
MCQ
उत्तर
219.2 pm
Explanation:
a = 620 pm
For fee unit cell, r = `"a"/(2sqrt2)`
`therefore "r" = 620/(2 xx 1.414)` = 219.2 pm
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Crystal Structure
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