मराठी

You are provided with a fine white coloured powder which is either sugar or salt. How would you identify it without tasting? - Science

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प्रश्न

You are provided with a fine white coloured powder which is either sugar or salt. How would you identify it without tasting?

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उत्तर

On heating, sugar powder is charred and becomes black while salt does not char. When dissolved in water, the salt solution will conduct electricity because it is ionic while sugar solution will not conduct electricity because it is covalent.

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पाठ 3: Atoms and Molecules - Short Answer Questions [पृष्ठ २१]

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एनसीईआरटी एक्झांप्लर Science [English] Class 9
पाठ 3 Atoms and Molecules
Short Answer Questions | Q 22. | पृष्ठ २१

व्हिडिओ ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्‍न

TRUE \ FALSE

Elements combine in definite proportions to form compounds.


TRUE \ FALSE

Neils Bohr gave the theory to explain the arrangement of protons in an atom.


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Acetic acid


Name two particles found inside the nucleus. What are they collectively called ?


What are orbits or shells ?


State Dalton’s atomic theory.


Name the particle or particles you would expect to find in :

The orbit of an atom


Fill in the blank

A charged particle is called an _____


Which has more atoms, 50 g of aluminium or 50 g of iron ? Illustrate your answer with the help of calculations.

(Atomic masses : Al = 27 u ; Fe = 25 u)


Give brief information of three subatomic particles with reference to electrical charge, mass and location.


Draw the electron dot structure of this compound. 


Compare: 

Chlorine atom and chloride ion, with respect to

Atomic structure
Electrical state


Elements X and Y have 1 and 7 electrons in their outermost shell respectively.

Which will form positive ion?


Define the following term with an example.

Element 


Rewrite the given sentence in correct form.

Elements contain two or more kind of atoms and compounds contain only one kind of atom.


What is the fundamental particle of an element?


The first scientific theory about atoms was given by J J. Thomson.


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