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Question
`int_0^{pi/2} (cos2x)/(cosx + sinx)dx` = ______
Options
-1
1
0
2
MCQ
Fill in the Blanks
Solution
`int_0^{pi/2} (cos2x)/(cosx + sinx)dx` = 0
Explanation:
`int_0^{pi/2} (cos2x)/(cosx + sinx)dx`
= `int_0^{pi/2} (cos^2x - sin^2x)/(cosx + sinx)dx`
= `int_0^{pi/2} (cosx - sinx)dx`
= `[sinx + cosx]_0^{pi"/"2} = 0`
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