Question

0.0210 M solution of N₂O₅ is allowed to decompose at 43°C. How long will it take to reduce to 0.0150 M?
(Given k = 6.0 × 10⁻⁴ sec⁻¹)

Options

• 3364 sec

• 360.0 sec

• 560.0 sec

• 5600 sec

Answer 1

560.0 sec

Explanation:

t = `2.303/"k" log_10  (["A"]_0)/(["A"]_"t")`

= `2.303/(6.0 xx 10^-4) log_10  ([0.021])/([0.015])`

= 3838 log₁₀ 1.4

= 3838 × 0.1461

= 560 sec