Question

0.05 M NaOH solution offered resistance of 31.6 ohms in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm^-1, calculate the molar conductivity of the NaOH solution.

Answer 1

Given, Molarity of NaOH solution = 0.05 M
Resistance = 31.6 ohm
Cell constant = 0.367 cm^-1

Now,

Molar conductivity = `"Specific conductivity × 1000"/"Molarity"`

= `"cell constant"/"Resistance" xx 1000/"Molarity"`

`(0.367 xx 1000)/(31.6 xx 0.05)`

m = 232.3 ohm^-1cm²mol^-1