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Question
0.32 g of an organic compound, after heating with fuming nitric acid and barium nitrate crystals is a sealed tube game 0.466 g of barium sulphate. Determine the percentage of sulphur in the compound.
Solution
Mass of the substance taken = 0.32 g
Mass of BaSO4 formed = 0.466 g
Molecular mass of BaSO4 = 137 + 32 + 64 = 233
Then, mass of S in 0.466 g of BaSO4 = `(0.466 xx 32)/233`
Percentage of S in compound = `(0.466 xx 32 xx100)/(233xx0.32)` = 20 %
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