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Question
`int(1-x)^-2 dx` = ______
Options
`(1-x)^-1 + c`
`(1+x)^-1 + c`
`(1-x)^-1 - 1 + c`
`(1-x)^-1 + 1 + c`
MCQ
Fill in the Blanks
Solution
`int(1-x)^-2 dx` = `bb((1-x)^-1 + c)`
Explanation:
`int(1-x)^-2 dx = (1-x)^(-2+1)/((-2+1)).d/dx (1-x) + c`
`= (1-x)^-1/((-1)). (0-1) + c`
`=(1-x)^-1 + c`
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