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Question
2 A 40 kg boy whose legs are 4 cm in area and 50 cm long falls through a height of 2 m without breaking his leg bones. If the bones can withstand stress of 0.9 x 108 N/m2. The Young's modulus for the material of the bone is ______.
Options
0.9 × 108 N/m2
5 × 108 N/m2
2.05 × 109 N/m2
2.05 × 108 N/m2
Solution
2 A 40 kg boy whose legs are 4 cm in area and 50 cm long falls through a height of 2 m without breaking his leg bones. If the bones can withstand stress of 0.9 × 108 NI m2. The Young's modulus for the material of the bone is 2.05 × 109 N/m2.
Explanation:
Loss in gravitational energy = gain in stress - strain
energy i.e., mgh = `1/2`(stress × strain × volume) × 2
`=> "Y" = (("stress")^2 xx "volume")/"mgh"`
`= ((1 xx 10^8)^2 xx 4 xx 50 xx 10^-6)/(40 xx 10 xx 2) = 2.05 xx 10^9`N/m2