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200 Men Have Provisions for 30 Days. If 50 Men Left, the Same Provisions Would Last for the Remaining Men, in How Many Days? - Mathematics

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Question

200 men have provisions for 30 days. If 50 men left, the same provisions would last for the remaining men, in how many days?

Sum

Solution

200 men have provisions for = 30 days

1 man will have provisions for = 30 x 200 days

200 – 50 = 150 men will have provisions

for = `(30 xx 200)/150` days = 40 days

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Concept of Unitary Method (Including Time and Work)
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Chapter 7: Unitary Method (Including Time and Work) - Exercise 7 (A)

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Selina Concise Mathematics [English] Class 7 ICSE
Chapter 7 Unitary Method (Including Time and Work)
Exercise 7 (A) | Q 8
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