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Question
2000 calories of radiant heat is incident on a body. If the body absorbs 550 calories of heat, find the coefficient of emmission of the body.
Numerical
Solution
Given: Q = 2000 cal, Qa = 550 cal
We have,
`a=Q_a/Q=550/2000`
`=11/40=0.275`
By Kirchhoff's law of radiation
a = e
e = 0.275
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Interpretation of Temperature in Kinetic Theory
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