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32−[48÷36−(27−¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯16−9)] - Mathematics

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Question

\[32 - [48 \div {36 - (27 - \overline{{16 - 9}})}] = ?\]

Options

  • 29

  • \[\frac{520}{17}\]
  • none of these

MCQ
Sum

Solution

29
Explanation:
Given expression:
= \[32 - [48 \div {36 - (27 - \overline{{16 - 9}})}] \]

= 32 − [48 ÷ {36 − ( 27 − 7)}] (Removing bar)
= 32 − [48 ÷ {36 − 20}] (Removing parentheses)
= 32 − [48 ÷ 16] (Removing braces)
= 32 − 3 (Removing square brackets)
= 29

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Chapter 6: Simplification - Exercise 6B [Page 108]

APPEARS IN

RS Aggarwal Mathematics [English] Class 6
Chapter 6 Simplification
Exercise 6B | Q 9 | Page 108

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