Question

4(2x – 3)² – (2x – 3) – 14 = 0

Answer 1

`4(2x - 3)^2 - (2x - 3) -  14 = 0`

Let 2x -  3= y

then `4y^2 - y - 14 = 0`

`=> 4y^2 - 8y + 7y - 14 = 0`

`=> 4y(y - 2) + 7(y - 2) = 0`

`=> (y -2)(4y + 7) = 0`

if y - 2 =0 or 4y + 7 = 0

=> y = 2 or y = `(-7)/4`

`=> 2x =5 or 2x = 5/4`

`=> x = 5/2 or x = 5/8`