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Question
4 tables and 3 chairs, together, cost Rs 2,250 and 3 tables and 4 chairs cost Rs 1950. Find the cost of 2 chairs and 1 table.
Solution
Let the cost of a table be Rs x and that of chairs be. Rs y Then,
4x + 3y = 2250 ....(i)
3x + 4y = 1950 ....(ii)
Multiplying equation (i) by 4 and equation (ii) by 3, we get
16x + 12y = 9000 ...(iii)
9x + 12y = 5850 .....(iv)
Subtracting equation (iv) by equation (iii), we get
16x - 9x = 9000 - 5850
=> 7x = 3150
`=> x = 3150/7 = 450`
Putting x = 450 in equation (i), we get
`4 xx 450 + 3y = 2250`
=> 1800 + 3y = 2250
=> 3y = 2250 - 1800
=> 3y = 450
`=> y = 450/3 = 150`
`=> 2y = 2 xx 150 = 300`
Cost of 2 chairs = Rs 300 and cost of 1 table = Rs 450
∴ The cost of 2 chairs and 1 table = 300 + 450 = Rs 750
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