Advertisements
Advertisements
Question
40 ml of methane is completely burnt using 80 ml of oxygen at room temperature The volume of gas left after cooling to room temperature is
Options
40 ml CO2 gas
40 ml CO2 gas and 80 ml H2O gas
60 ml CO2 gas and 60 ml H2O gas
120 ml CO2 gas
MCQ
Solution
40 ml CO2 gas
Explanation:
\[\ce{CH4_{(g)} + 2O2_{(g)} -> CO2_{(g)} + 2H2O_{(l)}}\]
Content | CH4 | O2 | CO2 |
Stoichiometric coefficient | 1 | 2 | 1 |
Volume of reactants allowed to react | 40 mL | 80 mL | - |
Volume of reactant reacted and product formed | 40 mL | 80 mL | 40 mL |
Volume of gas after cooling to the room temperature | - | - | - |
Since the product was cooled to room temperature, water exists mostly as liquid. Hence, 40 ml CO2 gas is correct.
shaalaa.com
Is there an error in this question or solution?