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45 – 38 – {60 ÷ 3 – (6 – 9 ÷ 3) ÷ 3} - Mathematics

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Question

45 – [38 – {60 ÷ 3 – (6 – 9 ÷ 3) ÷ 3}]

Sum

Solution

45 – [38 – {60 ÷ 3 – (6 – 9 ÷ 3) ÷ 3}]

= 45 - [38 - {60 ÷ 3 - (6 - 3)÷ 3}]

= 45 - [38 - {20 - 3 ÷ 3}]

= 45 - [38 - {20 -1}]

= 45 - [38 - 19]

= 45 - 19

= 26

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Properties of Operations on Integers
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Chapter 1: Integers - Exercise 1 (C)

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Selina Concise Mathematics [English] Class 7 ICSE
Chapter 1 Integers
Exercise 1 (C) | Q 7
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