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Question
476** 0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's places are respectively
Options
7 and 4
7 and 5
8 and 5
Cannot be determined
MCQ
Solution
Cannot be determined
Explanation
Let the given number be 476 xy 0.
Then, (4 + 7 + 6 + x + y + 0)
= (17 + x + y) must be divisible by 3 and
(0 + x + 7) - (y + 6 + 4) = (x - y - 3) must be either 0
or multiple of 11.
x - y - 3 = 0 ⇒ y = x - 3
Then, (17 + x + y) = (17 + x + x - 3)
= (2x+ 14) ⇒ x = 2 or x = 8 or x = 5
∴ x = 8 and y = 5 or x = 5 and y = 2
Hence, option Cannot be determined is correct.
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Number System (Entrance Exam)
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