Question

500 g of water and 100 g of ice at 0°C are in a calorimeter whose water equivalent is 40 g. 10 g of steam at 100°C is added to it. Then water in the calorimeter is ______.

(Latent heat of ice = 80 cal/g, Latent heat of steam = 540 cal/g)

Options

• 580 g

• 590 g

• 600 g

• 610 g

Answer 1

500 g of water and 100 g of ice at 0°C are in a calorimeter whose water equivalent is 40 g. 10 g of steam at 100°C is added to it. Then water in the calorimeter is 590 g.

Explanation:

As 1 g of steam at 100°C melts 8 g of ice at 0°C.

10 g of steam will melt 8 × 10 g of ice at 0°C.

Water in calorimeter = 500 + 80 + 10 g = 590 g