Question

540 g of ice at 0°C is mixed with 540 g of water at 80°C. The final temperature of the mixture will be ______.

Options

• 53.3°C

• 56.6°C

• 60.6°C

• 62.3°C

Answer 1

540 g of ice at 0°C is mixed with 540 g of water at 80°C. The final temperature of the mixture will be 53.3°C.

Explanation:

From the principle of calorimetry,

`m_1s_1DeltaT_1 = m_2s_2DeltaT_2`

`540 xx s_w(80 - T) = 540 xx s_w/2 xx (T - 0)`

where s_w is the specific heat of the water.

⇒ T = `160/3  ^circC = 53.3^circC`