Question

67.2 litres of hydrogen combines with 44.8 litres of nitrogen to form ammonia under specific conditions as:

\[\ce{N2_{(g)} + 3H2_{(g)} -> 2NH3_{(g)}}\]

Calculate the volume of ammonia produced. What is the other substance, if any, that remains in the resultant mixture?

Answer 1

According to the equation,

\[\ce{N2_{(g)} + 3H2_{(g)} -> 2NH3_{(g)}}\]

One mole of nitrogen combines with 3 moles of hydrogen to give 2 moles of ammonia.

∴ 3 × 22.4 litre of hydrogen require = 22.4 L of nitrogen

Since nitrogen is present in excess amounts, it remains the resultant.

Mixture and volume of ammonia produced = 2 × 22.4 L 

= 44.8 L