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Question
70 cal of heat is required to raise the temperature of 2 moles of an ideal gas at constant pressure from 30°C to 35°C. The amount of heat required to raise the temperature of the gas through the same range at constant volume will be (assume R = 2 cal/mol-K).
Options
30 cal
50 cal
70 cal
90 cal
MCQ
Solution
50 cal
Explanation:
QP = heat needed at constant pressure = nCp Δt
Qv = heat required at constant volume = nCv Δt
QP = 70 = 2 × Cp × (35° - 30°)
Now, CP = 7 cal/mol-K
CP - Cv = R
So, 7 - Cv = 2 ⇒ Cv = 5 col/mol-k
Qv = nCv Δt = 2 × 5 × (35° - 30°) = 50 cal
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