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Question
8.2 grams of calcium nitrate is decomposed by heating according to the equation
\[\ce{2Ca(NO3)2 -> 2CaO + 4NO2 + O2}\]
Calculate the following:
Volume of nitrogen dioxide obtained at STP
[Atomic weights: Ca − 40, N − 14, 0 − 16]
Sum
Solution
328 g of calcium nitrate liberated
4 × 22.4 lit of NO2
8.2 g of calcium nitrate liberated
`(4 × 22.4 × 8.2)/328`
= 2.24 lit of NO2
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Laboratory Preparation of Nitrogen Dioxide
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8.2 grams of calcium nitrate is decomposed by heating according to the equation
\[\ce{2Ca(NO3)2 -> 2CaO + 4NO2 + O2}\]
Calculate the following:
Mass of CaO formed
[Atomic weights: Ca - 40 , N - 14, 0 - 16]
