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A 10-meter wire is kept in east-west direction. It is falling down with a speed of 5.0 meter/second, perpendicular to the horizontal component of earth's magnetic field of 0.30 × 10−4 weber/meter2. -

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Question

A 10-meter wire is kept in east-west direction. It is falling down with a speed of 5.0 meter/second, perpendicular to the horizontal component of earth's magnetic field of 0.30 × 10−4 weber/meter2. The momentary potential difference induced between the ends of the wire will be:

Options

  • 0.0015 V

  • 0.015 V

  • 0.15 V

  • 1.5 V

MCQ

Solution

0.0015 V

Explanation:

If a wire, ℓ meter in length, moves perpendicular to a magnetic field of B weber/meter2 with a velocity of v meter/second, then the e.m.f. induced in the wire is given by

V = Bvℓ volt

Here, B = 0.30 × 10−4  weber/meter2,

v = 5.0 meter/second and ℓ = 10 meter

∴ B = 0.30 × 10−4 × 5.0 × 10 = 0.0015 volt

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