Question

A 100 g of sample of haemoglobin on analysis was found to contain 0.34% Fe by mass. If each haemoglobin molecule has four Fe²⁺ ions, the molecular mass of haemoglobin is: (Fe = 56 amu)

Options

• 77099.9 g

• 12735 g

• 65882 g

• 96359.9 g

Answer 1

65882 g

Explanation:

100 g Haemoglobin contains Fe = 0.34 g

1 mole haemoglobin contains Fe = 4 mole Fe²⁺

= 4 × 56

= 224 g

0.34 g Fe is present in haemoglobin = 100 g

224 g Fe is present in haemoglobin = `100/0.34 xx 224`

= 65882 g