Question

A 25 watt lamp is connected to a.c. potential of peak value 100 V. Calculate the rms value of the current.

Answer 1

Given: `barp` = 25 W, e₀ = 100 V

`barp=(e_0I_0)/2`

`I_0=(2barp)/e_0=(2xx25)/100`

`I_0=0.5 A`

`I_(rms)=I_0/sqrt(2)=0.5/1.414=0.3536 A`