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Question
`a^2b^2x^2+b^2x-1=0`
Solution
`a^2b^2x^2+b^2x-a^2x-1=0`
`⇒b^2x(a^2x+1)-1(a^2x+1)=0`
`⇒(b^2x-1)(a^2x+1)=0`
`⇒(b^2x-1)=0 or (a^2x+1)=0`
`⇒x=1/b^2 or x=(-1)/a^2`
Hence, `1/b^2` and `1/a^2` are the roots of the given equation.
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