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A 60 G Bullet Fired from a 5 Kg Gun Leaves with a Speed of 500 M/S. Find the Speed (Velocity) with Which the Gun Recoils (Jerks Backwards). - Science

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Question

A 60 g bullet fired from a 5 kg gun leaves with a speed of 500 m/s. Find the speed (velocity) with which the gun recoils (jerks backwards).

Short Note

Solution

Here , mass of bullet = 60 g
= `60/1000`
= 0.06 kg
velocity of bullet = 500 m/s
mass of gun = 5 kg
Now, putting these values in the formula:
Mass of bullet × Velocity of bullet = Mass of gun × Recoil velocity of gun
We get,
0.06 × 500 – 5 × Recoil velocity of gun
Recoil velocity of gun = `(0.06 xx 500)/5`
= `(0.06 xx 500)/5`
= `(0.06 xx 500)/5`
= 0.06 xx 100
Recoil velocity of gun = 6 m/s

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Chapter 2: Force and Laws of Motion - Very Short Answers 2 [Page 75]

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Lakhmir Singh Physics (Science) [English] Class 9 ICSE
Chapter 2 Force and Laws of Motion
Very Short Answers 2 | Q 25 | Page 75

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