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Question
A, B and C are the chemical properties of sulphuric acid:
A. Oxidizing agent
B. Dehydrating agent
C. Non-volatile acid
Match the following equations 1 to 3 to the above chemical properties of sulphuric acid.
1. \[\ce{KNO3 + H2SO4 -> KHSO4 + HNO3}\]
2. \[\ce{C12H22O11 -> 12C + 11H2O}\]
3. \[\ce{S + 2H2SO4 -> 2H2O + 3SO2}\]
Solution
The chemical properties of sulphuric acid along with their correct chemical equation is given below in the table:
| Chemical Properties | Chemical Equations |
| A. Oxidizing agent | 3. \[\ce{S + 2H2SO4 -> 2H2O + 3SO2}\] |
| B. Dehydrating agent | 2. \[\ce{C12H22O11 -> 12C + 11H2O}\] |
| C. Non-volatile acid | 1. \[\ce{KNO3 + H2SO4 -> KHSO4 + HNO3}\] |
Explanation:
(A) Sulphuric acid is a strong oxidising agent which means it can easily add oxygen to other elements or compounds. So, it is used to oxidise sulphur to sulphur dioxide.
(B) Sulphuric acid is a very strong acid therefore it can easily remove water from carbohydrates like sucrose (C12H22O11). In this reaction pure form of carbon is obtained along with water.
(C) Sulphuric acid has a high boiling point, therefore, it is considered almost non-volatile in nature and hence this property is used in the manufacturing of other volatile mineral acids like HNO3. Therefore, the reaction of sulphuric acid with potassium nitrate represents the non-volatile character of sulphuric acid.
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