Question

A ball falls from a height of 1 m on a ground and it loses half its kinetic energy when it hits the ground. What would be the total distance covered by the ball after sufficiently long time?

Options

• 1

• 2

• 3

• 4

Answer 1

3

Explanation:

`1/2"v"'^2 = 1/2(1/2"v"^2)`

∴ v' = `1/sqrt2"v"`

∴ e = `1/sqrt2`

Now d = h`[(1+"e"^2)/(1-"e"^2)]`

= 1 `[(1+(1//sqrt2)^2)/(1-(1//sqrt2)^2)]`

= `(1+1//2)/(1-1//2)`

= `(3/2)/(1/2)`

= 3.00