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Question
A battery of 10 volt carries 20,000 C of charge through a resistance of 20 Ω. The work done in 10 seconds is:
Options
2 × 103 joule
2 × 105 joule
2 × 104 joule
2 × 102 joule
MCQ
Solution
2 × 105 joule
Explanation:
W = qV = 20000 × 10 = 2,00,000 = 2 × 105 J
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