Question

A block of mass 20 kg is sliding on a surface is inclined at an angle of 45° with the horizontal. What will be the acceleration of the block if the coefficient of kinetic friction between the block and the surface is 0.7?

Options

• 2.01 m/s²

• 2.08 m/s²

• 3.08 m/s²

• None of these

Answer 1

2.08 m/s²

Explanation:

Acceleration down the inclined plane

a = g (sin θ − μ_k cos θ)

a = `9.8 (1/sqrt2 - 0.71/sqrt2)`

a = `9.8/sqrt2 (1 - 0.7)`

a = 2.08