Question

A body executing SHM has amplitude of 4 cm. What is the distance at which the body has equal value of both K.E. and P.E.?

Options

• `2 sqrt2  "cm"`

• `1/sqrt2  "cm"`

• `sqrt2  "cm"`

• `sqrt2/6  "cm"`

Answer 1

`2 sqrt2  "cm"`

Explanation:

Here K.E. = P.E.

`1/2 "m"omega^2 ("A"^2 - "y"^2) = 1/2 "m"omega^2"y"^2`

`"y" = "A"/sqrt2 = 4/sqrt2`

` = 2sqrt2  "cm"`