Question

A body is thrown from a point with speed 50 m/s at an angle 37° with horizontal. When it has moved a horizontal distance of 80 m then its distance from point of projection is ______.

Options

• 40 m

• 40 `sqrt2` m

• 40 `sqrt5` m 

• None

Answer 1

A body is thrown from a point with speed 50 m/s at an angle 37° with horizontal. When it has moved a horizontal distance of 80 m then its distance from point of projection is 40 `bb(sqrt5)` m.

Explanation:

As y = x tanθ = `-("g"x^2)/(2"u"^2cos^2theta)`

y = `80xx3/4-(10xx80xx80xx25)/(2xx50xx50xx16))`

= 40 m

∴ distance from point of projection

= `sqrt((80)^2+(40)^2)`m

= 40`sqrt5`m