Advertisements
Advertisements
Question
A body of mass 0.5 kg is rotating in a vertical circle of radius 2 m. What will be the difference in its kinetic energy at the top and bottom of the circle? (Take g = 9.8 m/s2)
Options
10.3 J
20.9 J
19.6 J
50 J
MCQ
Solution
19.6 J
Explanation:
From conservation of energy,
`("K.E.")_"bottom" = ("K.E.")_"top" + ("P.E.")_"top"`
`therefore 1/2 "mv"_1^2 = 1/2 "mv"_2^2 + "mg" (2"r")`
`therefore "Change in K.E. is,"`
`therefore 1/2 "mv"_1^2 - 1/2 "mv"_2^2 = "mg" (2"r")`
`= 0.5 xx 9.8 xx 2 xx 2`
` = 19.6 "J"`
shaalaa.com
Vertical Circular Motion
Is there an error in this question or solution?
