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A body of mass 37 kg rests on a rough horizontal surface. The minimum horizontal force required to just start the motion is 68.5 N. In order to keep the body moving with constant velocity, a force of - Physics

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Question

A body of mass 37 kg rests on a rough horizontal surface. The minimum horizontal force required to just start the motion is 68.5 N. In order to keep the body moving with constant velocity, a force of 43 N is needed. What is the value of coefficient of static friction?

Numerical

Solution

Given: FL = 68.5 N, Fk = 43 N, m = 37 kg, g = 9.8 m/s2

To find: Coefficient of static friction (μS)

Formula: μ= `("F"_"L")/"N" = ("F"_"L")/"mg"`

Calculation:

From formula,

∴ `mu_"s" = "F"_"s"/"N"`

= 68.5/(37 xx 9.8)`

= 0.1889

∴ The coefficient of static friction is 0.1889.

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Friction in Solids
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Chapter 6: Mechanical Properties of Solids - Exercises [Page 113]

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Balbharati Physics [English] 11 Standard Maharashtra State Board
Chapter 6 Mechanical Properties of Solids
Exercises | Q 5. iii). a) | Page 113
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