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Question
A box contains 6 pens, 12 of which are defective. Two pens are taken randomly from the box. If r.v. X : number of defective pens obtained, then standard deviation of X = ______.
Options
`± 4/(3sqrt(5))`
`8/3`
`16/45`
`4/(3sqrt(5))`
Solution
A box contains 6 pens, 12 of which are defective. Two pens are taken randomly from the box. If r.v. X : number of defective pens obtained, then standard deviation of X = `underlinebb(4/(3sqrt(5)))`.
Explanation:
Given, X is the number of defective pens obtained. Two pens are defective.
So, X has possible values 0, 1, 2
Now, P(X = 0) = `(""^4C_2)/(""^6C_2) = (4 xx 3)/(6 xx 5) = 6/15`
P(X = 1) = `(""^2C_1 xx ""^4C_1)/(""^6C_2) = 8/15`
P(X = 2) = `(""^2C_2)/(""^6C_2) = (1 xx 2)/(6 xx 5) = 1/15`
E(X2) = `8/15 + 2^2/15 = 12/15 = 4/5`
Standard deviation = `sqrt(E(X^2) - [E(X)]^2)`
= `sqrt((4/5) - (2/3)^2`
= `sqrt(16/45)`
= `4/(3sqrt(5))`