Question

A bullet of mass 20g moving with a velocity of 200 m/s strikes a target and is brought to rest in `(1/50)^"th"` of a second. The impulse and average force of impact are respectively ______.

Options

• 2 Ns, 100 N

• 4 Ns, 200 N

• 2 Ns, 200 N

• 4 Ns, 100 N

Answer 1

A bullet of mass 20g moving with a velocity of 200 m/s strikes a target and is brought to rest in `(1/50)^"th"` of a second. The impulse and average force of impact are respectively 4 Ns, 200 N.

Explanation:

Initial momentum P₁ = mV = 20 × 10^-3 kg × 200 m/s

= 4 kg m/s

final momentum = 0

Change in momentum = 4 kg m/s

Impulse = change in momentum = 4 kg m/s = 4 Ns

Force = `"Impulse"/"time"="4Ns"/((1/50)s)=200  "N"`