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Question
A car covers 90 km in `1 1/2` hours towards east. Calculate
- displacement of car,
- its velocity in (a) kmh−1 (b) ms−1.
Solution
(i) A car covers 90 km in `1 1/2` hour i.e. `3/2` hour towards east.
∴ Displacement = 90 km − east
(ii) Time = `1 1/2` hour = `3/2` hour
Velocity = `"Displacement"/"Time"`
v = `90/(3//2)`
v = `(90xx2)/3` = 60 km/h
v = `60xx1000/3600` m/s
v = `100/6` m/s = 16.67 ms−1
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