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Question
A cell of internal resistance r is connected across an external resistance nr. Then the ratio of the terminal voltage to the emf of the cell is ______.
Options
`1/"n"`
`1/("n"+1)`
`"n"/("n"+1)`
`("n"-1)/"n"`
MCQ
Fill in the Blanks
Solution
A cell of internal resistance r is connected across an external resistance nr. Then the ratio of the terminal voltage to the emf of the cell is `underlinebb("n"/("n"+1))`.
Explanation:
Internal resistance = r,
External resistance = nr
Let terminal voltage = V
then V = E - Ir ⇒ V = E - `"Er"/(("n"+1)"r")`
V = `"nE"/("n"+1)`
⇒ `"V"/"E"`
= `"n"/("n"+1)`
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Potentiometer
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